Estimation and Approximation

estimation and approximation class 6 selina

Table of Contents

Exercise: 2-B

Q1: Estimate the sum of each pair of numbers to the nearest ten:

i. 34 and 87
34 ≈ 30, 87 ≈ 90
30 + 90 = 120

ii. 78 and 18
78 ≈ 80, 18 ≈ 20
80 + 20 = 100

iii. 96 and 55
96 ≈ 100, 55 ≈ 60
100 + 60 = 160

iv. 76 and 62
76 ≈ 80, 62 ≈ 60
80 + 60 = 140

v. 457 and 175
457 ≈ 460, 175 ≈ 180
460 + 180 = 640

vi. 527 and 267
527 ≈ 530, 267 ≈ 270
530 + 270 = 800


Q2: Estimate the sum of each pair of numbers to the nearest hundred:

i. 336 and 782
336 ≈ 300, 782 ≈ 800
300 + 800 = 1100

ii. 270 and 495
270 ≈ 300, 495 ≈ 500
300 + 500 = 800

iii. 4280 and 5295
4280 ≈ 4300, 5295 ≈ 5300
4300 + 5300 = 9600

iv. 30047 and 39287
30047 ≈ 30000, 39287 ≈ 39300
30000 + 39300 = 69300


Q3: Estimate the sum of the following pairs of numbers to the nearest thousand:

i. 53826 and 36455
53826 ≈ 54000, 36455 ≈ 36000
54000 + 36000 = 90000

ii. 56802 and 22475
56802 ≈ 57000, 22475 ≈ 22000
57000 + 22000 = 79000


Q4: Estimate the following differences correct to the nearest ten:

i. 82 – 27
82 ≈ 80, 27 ≈ 30
80 – 30 = 50

ii. 96 – 36
96 ≈ 100, 36 ≈ 40
100 – 40 = 60

iii. 508 – 248
508 ≈ 510, 248 ≈ 250
510 – 250 = 260


Q5: Estimate each difference to the nearest hundred:

i. 769 – 314
769 ≈ 800, 314 ≈ 300
800 – 300 = 500

ii. 856 – 687
856 ≈ 900, 687 ≈ 700
900 – 700 = 200

iii. 6352 – 2086
6352 ≈ 6400, 2086 ≈ 2100
6400 – 2100 = 4300


Q6: Estimate each difference to the nearest thousand:

i. 45974 – 38766
45974 ≈ 46000, 38766 ≈ 39000
46000 – 39000 = 7000

ii. 76003 – 48399
76003 ≈ 76000, 48399 ≈ 48000
76000 – 48000 = 28000


Q7: Estimate each of the following products by rounding off each number to the nearest ten :

i. 49 × 52
49 ≈ 50, 52 ≈ 50
50 × 50 = 2500

ii. 63 × 38
63 ≈ 60, 38 ≈ 40
60 × 40 = 2400

iii. 27 × 54
27 ≈ 30, 54 ≈ 50
30 × 50 = 1500

iv. 53 × 85
53 ≈ 50, 85 ≈ 90
50 × 90 = 4500

v. 74 × 67
74 ≈ 70, 67 ≈ 70
70 × 70 = 4900

vi. 25 × 33
25 ≈ 30, 33 ≈ 30
30 × 30 = 900


Q8: Estimate each of the •following products by rounding off each number to the nearest hundred:

i. 477 × 213
477 ≈ 500, 213 ≈ 200
500 × 200 = 100000

ii. 624 × 236
624 ≈ 600, 236 ≈ 200
600 × 200 = 120000

iii. 333 × 247
333 ≈ 300, 247 ≈ 200
300 × 200 = 60000

iv. 537 × 283
537 ≈ 500, 283 ≈ 300
500 × 300 = 150000

v. 382 × 127
382 ≈ 400, 127 ≈ 100
400 × 100 = 40000

vi. 472 × 328
472 ≈ 500, 328 ≈ 300
500 × 300 = 150000


Q9: Estimate each of the following products by rounding off the first number correct to the nearest ten and the other number correct to the nearest hundred:

i. 28 × 287
28 ≈ 30, 287 ≈ 300
30 × 300 = 9000

ii. 432 × 128
432 ≈ 430, 128 ≈ 100
430 × 100 = 43000

iii. 48 × 165
48 ≈ 50, 165 ≈ 200
50 × 200 = 10000

iv. 72 × 258
72 ≈ 70, 258 ≈ 300
70 × 300 = 21000

v. 83 × 664
83 ≈ 80, 664 ≈ 700
80 × 700 = 56000

vi. 44 × 250
44 ≈ 40, 250 ≈ 300
40 × 300 = 12000


Q10: Estimate each of the following quotients by rounding each number to the nearest ten:

i. 87 ÷ 28
87 ≈ 90, 28 ≈ 30
90 ÷ 30 = 3

ii. 84 ÷ 23
84 ≈ 80, 23 ≈ 20
80 ÷ 20 = 4

iii. 77 ÷ 22
77 ≈ 80, 22 ≈ 20
80 ÷ 20 = 4

iv. 198 ÷ 24
198 ≈ 200, 24 ≈ 20
200 ÷ 20 = 10

v. 355 ÷ 26
355 ≈ 360, 26 ≈ 30
360 ÷ 30 = 12

vi. 444 ÷ 42
444 ≈ 440, 42 ≈ 40
440 ÷ 40 = 11

vii. 843 ÷ 33
843 ≈ 840, 33 ≈ 30
840 ÷ 30 = 28


Q11: There are 768 houses in a town and about 7 people live in each house. Round off these two numbers to the nearest ten and estimate the total number of people living in the town.

768 ≈ 770, 7 ≈ 10
770 × 10 = 7700


Q12: There are 514 mango trees in an orchard. The owner plans to plant 178 more mango trees. Estimate how many mango trees will be there in the orchard, correct to the nearest hundred ?

514 ≈ 500, 178 ≈ 200
500 + 200 = 700


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