Rational Numbers

rational numbers class 8 rs aggarwal

Step by Step solutions of RS Aggarwal ICSE Class-8 Maths chapter 1- Rational Numbers by Goyal Brothers Prakashan is provided

Table of Contents

Exercise: 1-D

Q1: Find a rational number between each of the following pairs of rational numbers:

i. \(\frac{7}{10}\ and\ \frac{10}{17}\)

Let’s convert both to a common denominator using LCM(10,17) = 170. \[ \frac{7}{10} = \frac{7 \times 17}{10 \times 17} = \frac{119}{170}, \\ \frac{10}{17} = \frac{10 \times 10}{17 \times 10} = \frac{100}{170} \]Now check: \[ \frac{100}{170} < \frac{119}{170} \\ \Rightarrow \text{So } \frac{109}{170} \text{ is between them.} \]Answer: One rational number between them is \( \frac{109}{170} \)

ii. \(1\frac{3}{8}\ and\ 2\)

Convert mixed number to improper fraction: \[ 1\frac{3}{8} = \frac{11}{8} \]Now: \[ \frac{11}{8} < x < \frac{16}{8} \\ \Rightarrow \frac{12}{8}, \frac{13}{8}, \frac{14}{8}, \dots \text{ are between them.} \]Answer: One rational number between them is \( \frac{13}{8} \)

iii. \(\frac{-3}{5}\ and\ \frac{-4}{7}\)

Convert to common denominator using LCM(5,7) = 35: \[ \frac{-3}{5} = \frac{-21}{35}, \\ \frac{-4}{7} = \frac{-20}{35} \]Now: \[ \frac{-21}{35} < \frac{-20}{35} \\ \Rightarrow \text{Try } \frac{-205}{350} \text{ which lies between them} \\ \Rightarrow \frac{-41}{70} \]Answer: One rational number between them is \( \frac{-41}{70} \)

iv. \(-2\ and\ \frac{-17}{21}\)

Convert \( -2 \) to same denominator as \( \frac{-17}{21} \): \[ -2 = \frac{-42}{21} \\ \Rightarrow \frac{-42}{21} < x < \frac{-17}{21} \]Choose any number between them: \[ \frac{-30}{21} \text{ lies between } \frac{-42}{21} \text{ and } \frac{-17}{21} \]Answer: One rational number between them is \( \frac{-30}{21} \)


Q2: Find three rational numbers between:

i. \(4\ and\ 4\frac{2}{3}\)

Step 1: Convert mixed number to improper fraction: \[ 4 = \frac{4}{1},\\ 4\frac{2}{3} = \frac{14}{3} \]Step 2: Take LCM of denominators 1 and 3 = 3 \[ \frac{12}{3},\ \frac{14}{3} \]Step 3: To insert 3 numbers, multiply numerator and denominator of both by \(3 + 1 = 4\)\[ \frac{12 \times 4}{3 \times 4} = \frac{48}{12},\\ \frac{14 \times 4}{3 \times 4} = \frac{56}{12} \]Now rational numbers with denominator 12 and numerators between 48 and 56 are: \[ \frac{49}{12},\ \frac{50}{12},\ \frac{51}{12} \]Answer: Required numbers: \( \frac{49}{12},\ \frac{50}{12},\ \frac{51}{12} \)

ii. \(\frac{-1}{2}\ and\ \frac{-1}{4}\)

Step 1: Find LCM of 2 and 4 = 4 \[ \frac{-1}{2} = \frac{-2}{4},\\ \frac{-1}{4} = \frac{-1}{4} \]Step 2: Multiply numerator and denominator by \(3 + 1 = 4\) \[ \frac{-2 \times 4}{4 \times 4} = \frac{-8}{16},\\ \frac{-1 \times 4}{4 \times 4} = \frac{-4}{16} \]Now rational numbers with denominator 16 and numerators between -8 and -4 are: \[ \frac{-7}{16},\ \frac{-6}{16},\ \frac{-5}{16} \]Answer: Required numbers: \( \frac{-7}{16},\ \frac{-6}{16},\ \frac{-5}{16} \)

iii. \(2\ and\ 3\)

Step 1: Write as fractions with denominator 1: \[ 2 = \frac{2}{1},\\ 3 = \frac{3}{1} \]Step 2: Multiply numerator and denominator by \(3 + 1 = 4\) \[ \frac{2 \times 4}{1 \times 4} = \frac{8}{4},\\ \frac{3 \times 4}{1 \times 4} = \frac{12}{4} \]Now rational numbers between \( \frac{8}{4} \) and \( \frac{12}{4} \) are: \[ \frac{9}{4},\ \frac{10}{4},\ \frac{11}{4} \]Answer: Required numbers: \( \frac{9}{4},\ \frac{10}{4},\ \frac{11}{4} \)


Q3: Find five rational numbers between:

i. \(\frac{3}{5}\ and\ \frac{2}{3}\)

Step 1: Make denominators same (LCM of 5 and 3 = 15) \[ \frac{3}{5} = \frac{9}{15}, \\ \frac{2}{3} = \frac{10}{15} \]Step 2: Choose equivalent fractions with larger denominator (multiply numerator and denominator by 10) \[ \frac{9}{15} = \frac{90}{150}, \\ \frac{10}{15} = \frac{100}{150} \]Step 3: Pick five numbers between 90 and 100 (denominator 150) \[ \frac{91}{150}, \frac{92}{150}, \frac{93}{150}, \frac{94}{150}, \frac{95}{150} \]Answer: \( \frac{91}{150}, \frac{92}{150}, \frac{93}{150}, \frac{94}{150}, \frac{95}{150} \)

ii. \(-2\ and\ -1\frac{1}{2}\)

Step 1: Convert to improper fractions \[ -2 = \frac{-4}{2}, \\ -1\frac{1}{2} = \frac{-3}{2} \]Step 2: Multiply numerator and denominator by 10 \[ \frac{-4}{2} = \frac{-40}{20}, \\ \frac{-3}{2} = \frac{-30}{20} \]Step 3: Pick five values between -40 and -30 with denominator 20 \[ \frac{-39}{20}, \frac{-38}{20}, \frac{-37}{20}, \frac{-36}{20}, \frac{-35}{20} \]Answer: \( \frac{-39}{20}, \frac{-38}{20}, \frac{-37}{20}, \frac{-36}{20}, \frac{-35}{20} \)

iii. \(-3\ and\ -2\)

Step 1: Write with same denominator \[ -3 = \frac{-30}{10}, \\ -2 = \frac{-20}{10} \]Step 2: Pick values between -30 and -20 with denominator 10 \[ \frac{-29}{10}, \frac{-28}{10}, \frac{-27}{10}, \frac{-26}{10}, \frac{-25}{10} \]Answer: \( \frac{-29}{10}, \frac{-28}{10}, \frac{-27}{10}, \frac{-26}{10}, \frac{-25}{10} \)


Q4: Find 10 rational numbers between \(\frac{-3}{4}\ and\ \frac{5}{6}\).

Step 1: Find LCM of denominators 4 and 6 \[ \text{LCM}(4, 6) = 12 \]Step 2: Convert both fractions to have denominator 12 \[ \frac{-3}{4} = \frac{-9}{12}, \\ \frac{5}{6} = \frac{10}{12} \]Step 3: Multiply numerator and denominator by 10 for better spacing \[ \frac{-9}{12} = \frac{-90}{120}, \\ \frac{10}{12} = \frac{100}{120} \]Step 4: Choose 10 rational numbers between -90 and 100 (with denominator 120)
Pick 10 values between -90 and 100: \[ \frac{-80}{120}, \frac{-60}{120}, \frac{-40}{120}, \frac{-20}{120}, \frac{0}{120}, \frac{20}{120}, \frac{40}{120}, \frac{60}{120}, \frac{80}{120}, \frac{90}{120} \]Answer: \( \frac{-80}{120}, \frac{-60}{120}, \frac{-40}{120}, \frac{-20}{120}, \frac{0}{120}, \frac{20}{120}, \frac{40}{120}, \frac{60}{120}, \frac{80}{120}, \frac{90}{120} \)


Q5: Find 12 rational numbers between \(-1\ and\ 2\).

Step 1: Write -1 and 2 as rational numbers with same denominator
Let’s choose 13 as denominator to find 12 values in between (more spacing). \[ -1 = \frac{-13}{13}, \\ 2 = \frac{26}{13} \]Step 2: List 12 rational numbers between \( \frac{-13}{13} \) and \( \frac{26}{13} \)
We now choose 12 values between -13 and 26: \[ \frac{-12}{13}, \frac{-8}{13}, \frac{-4}{13}, \frac{0}{13}, \frac{2}{13}, \frac{5}{13}, \frac{9}{13}, \frac{12}{13}, \frac{15}{13}, \frac{18}{13}, \frac{21}{13}, \frac{24}{13} \]Answer: \( \frac{-12}{13}, \frac{-8}{13}, \frac{-4}{13}, \frac{0}{13}, \frac{2}{13}, \frac{5}{13}, \frac{9}{13}, \frac{12}{13}, \frac{15}{13}, \frac{18}{13}, \frac{21}{13}, \frac{24}{13} \)


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