Operation of Whole Numbers

Operation of whole numbers

Step by Step solutions of RS Aggarwal ICSE Class-6 Maths chapter 2- Operation of Whole Numbers by Goyal Brothers Prakashan is provided.

Table of Contents

Exercise: 2-C

Multiple Choice Type

Q1. The smallest whole number is

Step-by-step solution:
The whole numbers start from 0, not 1, so 1 is not the smallest whole number.
Thus, the smallest whole number is 0, and none of the options provide this.
Answer: d. none of these


Q2: The least number of 4 digit which is exactly divisible by 7 by is

Step-by-step solution:
The least 4-digit number is 1000. We need to find the smallest number divisible by 7.
1000 ÷ 7 = 142 remainder 6. So, 1000 is not divisible by 7.
We add 1 to make it 1001: 1001 ÷ 7 = 143 with no remainder.
Therefore, 1001 is the least 4-digit number divisible by 7.
Answer: c. 1,001


Q3: The largest number of 4 digits exactly divisible by 13 is

Step-by-step solution:
The largest 4-digit number is 9999. We divide it by 13 to check divisibility.
9999 ÷ 13 = 769 remainder 2. Therefore, 9999 is not divisible by 13.
We subtract the remainder (2) from 9999: 9999 – 2 = 9997.
9997 ÷ 13 = 769 with no remainder, so 9997 is divisible by 13.
Therefore, the largest 4-digit number divisible by 13 is 9997.
Answer: b. 9,997


Q4: What least number should be subtracted from 10003 to get a number exactly divisible by 11?

Step-by-step solution:
Divide 10003 by 11. \[ 10003 \div 11 \] On dividing, we get: \[ 10003 \div 11 = 909 \text{ remainder } 4 \]That is, \[ 10003 = 11 \times 909 + 4 \]Understand the meaning.
Here, remainder = 4.
To make 10003 exactly divisible by 11, we need to **remove** this remainder.
Thus, we need to subtract 4 from 10003.
Subtract the remainder. \[ 10003 – 4 = 9999 \]Verify divisibility.
Now, \[ 9999 \div 11 = 909 \]Quotient is 909 and remainder is 0.
Hence, 9999 is exactly divisible by 11.
Answer: b. 9,997


Q5: What least number should be added to 6,000 to get a number exactly divisible by 19?

Step-by-step solution:
6000 ÷ 19 = 315 remainder 15.
Difference = 19 – 15 = 4.
We add 4 to 6000: 6000 + 4 = 6004.
6004 ÷ 19 = 316 with no remainder, so it is divisible by 19.
Answer: d. 6


Q6: What whole number is nearest to 457 which is divisible by 11?

Step-by-step solution:
457 ÷ 11 = 41 remainder 6.
The nearest multiple of 11 is 462 (41 × 11 = 462).
Therefore, 462 is the closest number to 457 that is divisible by 11.
Answer: a. 462


Q7: How many whole numbers are there between 1,036 and 1,263?

Step-by-step solution:
We calculate the difference between the two numbers: 1,263 – 1,036 = 227.
Since we are counting the numbers between, we subtract 1 to this difference: 227 – 1 = 226.
Therefore, there are 226 whole numbers between 1,036 and 1,263.
Answer: c. 226


Q8: A number when divided by 43 gives 12 as quotient and 24 as remainder. The number is

Step-by-step solution:
Using the division rule: Dividend = (Divisor × Quotient) + Remainder.
So, Dividend = (43 × 12) + 24 = 516 + 24 = 540.
Thus, the number is 540.
Answer: d. 540


Q9: In a division sum, the dividend is 398, quotient is 15 and the remainder is 8. What is the divisor?

Step-by-step solution:
Using the division rule: Dividend = (Divisor × Quotient) + Remainder.
398 = (Divisor × 15) + 8.
398 – 8 = 390.
390 ÷ 15 = 26.
So, the divisor is 26.
Answer: b. 26


Q10: 8 × 273 × 125 = ?

Step-by-step solution:
We first calculate 8 × 273 = 2184.
Now, multiply 2184 by 125: 2184 × 125 = 273,000.
Thus, the correct answer is 2,73,000.
Answer: c. 2,73,000


Q11: 4 × 346 × 25 = ?

Step-by-step solution:
First, multiply 4 × 346 = 1384.
Now, multiply 1384 by 25: 1384 × 25 = 34,600.
Thus, the correct answer is 34,600.
Answer: d. 34,600


Q12: 13,729 × 93 + 13,729 × 7 = ?

Step-by-step solution:
We use the distributive property: 13,729 × (93 + 7) = 13,729 × 100.
Now, multiply 13,729 by 100: 13,729 × 100 = 23,62,900.
Thus, the correct answer is 23,62,900.
Answer: a. 23,62,900


Q13: 2,563 × 187 – 2,563 × 87 = ?

Step-by-step solution:
We factor the expression: 2,563 × (187 – 87) = 2,563 × 100.
Now, multiply 2,563 by 100: 2,563 × 100 = 2,56,300.
Thus, the correct answer is 2,56,300.
Answer: a. 2,56,300


Q14: 546 × 98 = ?

Step-by-step solution:
Multiply 546 by 98: 546 × (100 – 2) = 54600 – 1092 = 53,508.
Thus, the correct answer is 53,508.
Answer: b. 53,508


Q15: 8,456 – ? = 3,580

Step-by-step solution:
We rearrange the equation to find the missing number: 8,456 – ? = 3,580.
To find the missing number, subtract 3,580 from 8,456: 8,456 – 3,580 = 4,876.
Thus, the correct answer is 4,876.
Answer: c. 4,876


previous
next

Share the Post:

Leave a Comment

Your email address will not be published. Required fields are marked *

Related Posts​

  • Counters and Accumulators in Java
    Counters keep track of how many times an action happens in a program while Accumulators add up values to find a total. Both help Java programs remember and calculate changing numbers during execution.
  • Assignment Operator in Java
    Assignment operators in Java are used to assign or update values in variables. They make code simpler by combining operations and assignments.

Join Our Newsletter

Name
Email
The form has been submitted successfully!
There has been some error while submitting the form. Please verify all form fields again.

Scroll to Top