Linear Inequations

linear inequations class 8 rs aggarwal

Step by Step solutions of Exercise- 16 of RS Aggarwal ICSE Class-8 Maths chapter 16- Linear Inequations by Goyal Brothers Prakashan is provided.

Table of Contents

Exercise 16

Q1: If x ∈ {-3, -2, -1, 0, 1, 2, 3}, find the solution of each of the following inequations:

i. x + 2 < 1

Step 1: Subtract 2 from both sides:
x + 2 – 2 < 1 – 2
x < -1
Step 2: Check the values of x from {-3, -2, -1, 0, 1, 2, 3} that satisfy x < -1:
x = {-3, -2}
Answer: x = -3, -2

ii. 2x – 1 < 4

Step 1: Add 1 to both sides:
2x – 1 + 1 < 4 + 1
2x < 5
Step 2: Divide both sides by 2:
x < 5/2
Step 3: From x ∈ {-3, -2, -1, 0, 1, 2, 3}, x < 5/2 = 2.5:
x = -3, -2, -1, 0, 1, 2
Answer: x = {-3, -2, -1, 0, 1, 2}

iii. (2/3)x < 1

Step 1: Multiply both sides by 3/2:
x < 1 × 3/2
x < 3/2
Step 2: x ∈ {-3, -2, -1, 0, 1, 2, 3}, so x < 3/2 = 1.5:
x = -3, -2, -1, 0, 1
Answer: x = {-3, -2, -1, 0, 1}

iv. 1 – x > 0

Step 1: Subtract 1 from both sides:
1 – x – 1 > 0 – 1
-x > -1
Step 2: Multiply both sides by -1 (reverse inequality):
x < 1
Step 3: x ∈ {-3, -2, -1, 0, 1, 2, 3}, so x < 1:
x = -3, -2, -1, 0
Answer: x = {-3, -2, -1, 0}

v. 3 – 5x < -1

Step 1: Subtract 3 from both sides:
3 – 5x – 3 < -1 – 3
-5x < -4
Step 2: Divide by -5 (reverse inequality):
x > 4/5
Step 3: x ∈ {-3, -2, -1, 0, 1, 2, 3}, so x > 0.8:
x = 1, 2, 3
Answer: x = {1, 2, 3}

vi. 2 – 3x > 1

Step 1: Subtract 2 from both sides:
2 – 3x – 2 > 1 – 2
-3x > -1
Step 2: Divide by -3 (reverse inequality):
x < 1/3
Step 3: x ∈ {-3, -2, -1, 0, 1, 2, 3}, so x < 1/3:
x = -3, -2, -1, 0
Answer: x = {-3, -2, -1, 0}

vii. -6 ≥ 2x – 4

Step 1: Add 4 to both sides:
-6 + 4 ≥ 2x – 4 + 4
-2 ≥ 2x
Step 2: Divide both sides by 2:
-1 ≥ x
or x ≤ -1
Step 3: x ∈ {-3, -2, -1, 0, 1, 2, 3}, so x ≤ -1:
x = -3, -2, -1
Answer: x = {-3, -2, -1}

viii. 3x – 5 ≥ -12

Step 1: Add 5 to both sides:
3x – 5 + 5 ≥ -12 + 5
3x ≥ -7
Step 2: Divide by 3:
x ≥ -7/3
Step 3: x ∈ {-3, -2, -1, 0, 1, 2, 3}, so x ≥ -7/3 ≈ -2.33:
x = -2, -1, 0, 1, 2, 3
Answer: x = {-2, -1, 0, 1, 2, 3}

ix. 14 – 2x < 6

Step 1: Subtract 14 from both sides:
14 – 2x – 14 < 6 – 14
-2x < -8
Step 2: Divide by -2 (reverse inequality):
x > 4
Step 3: x ∈ {-3, -2, -1, 0, 1, 2, 3}, so no value satisfies x > 4
Answer: Φ


Q2: If x ∈ N, find the solution set of each of the following inequations:

i. 3x – 8 < 0

Step 1: Add 8 to both sides:
3x – 8 + 8 < 0 + 8
3x < 8
Step 2: Divide both sides by 3:
x < 8/3
Step 3: x ∈ N, so x < 8/3 ≈ 2.67
x = 1, 2
Answer: x = 1, 2

ii. 7x + 3 ≤ 17

Step 1: Subtract 3 from both sides:
7x + 3 – 3 ≤ 17 – 3
7x ≤ 14
Step 2: Divide both sides by 7:
x ≤ 2
Step 3: x ∈ N, so x = 1, 2
Answer: x = 1, 2

iii. 5 – x > 1

Step 1: Subtract 5 from both sides:
5 – x – 5 > 1 – 5
-x > -4
Step 2: Multiply both sides by -1 (reverse inequality):
x < 4
Step 3: x ∈ N, so x = 1, 2, 3
Answer: x = 1, 2, 3

iv. 1 – 3x > -4

Step 1: Subtract 1 from both sides:
1 – 3x – 1 > -4 – 1
-3x > -5
Step 2: Divide by -3 (reverse inequality):
x < 5/3
Step 3: x ∈ N, so x < 5/3 ≈ 1.67
x = 1
Answer: x = 1

v. 3/2 – x/2 > -1

Step 1: Subtract 3/2 from both sides:
3/2 – x/2 – 3/2 > -1 – 3/2
-x/2 > -5/2
Step 2: Multiply both sides by -2 (reverse inequality):
x < 5
Step 3: x ∈ N, so x = 1, 2, 3, 4
Answer: x = 1, 2, 3, 4

vi. -1/4 ≤ 1/2 – x/3

Step 1: Subtract 1/2 from both sides:
-1/4 – 1/2 ≤ 1/2 – 1/2 – x/3
-3/4 ≤ -x/3
Step 2: Multiply both sides by -3 (reverse inequality):
x ≤ 9/4
Step 3: x ∈ N, so x ≤ 9/4 ≈ 2.25
x = 1, 2
Answer: x = 1, 2


Q3: If x ∈ Z, find the solution of each of the following inequations. Represent each solution set on the number line.

i. 9x – 7 ≤ 25 + 3x

Step 1: Subtract 3x from both sides:
9x – 7 – 3x ≤ 25 + 3x – 3x
6x – 7 ≤ 25
Step 2: Add 7 to both sides:
6x – 7 + 7 ≤ 25 + 7
6x ≤ 32
Step 3: Divide both sides by 6:
x ≤ 32/6 = 16/3 ≈ 5.33
Step 4: x ∈ Z, so x ≤ 5
Answer: x = {…, -1, 0, 1, 2, 3, 4, 5}

Number line: 
°°°
←───|──|──|──|──|──|──|──|──|──|───→
   -3 -2 -1  0  1  2  3  4  5  6

ii. -17 < 9x – 8

Step 1: Add 8 to both sides:
-17 + 8 < 9x – 8 + 8
-9 < 9x
Step 2: Divide both sides by 9:
-1 < x
or x > -1
Step 3: x ∈ Z, so x = 0, 1, 2, …
Answer: x = {0, 1, 2, 3, 4, ….}

Number line: 
                                °°°
←───|──|──|──|──|──|──|──|──|──|───→
   -3 -2 -1  0  1  2  3  4  5  6

iii. -4(x + 5) > 10

Step 1: Divide both sides by -4 (reverse inequality):
x + 5 < 10 / -4
x + 5 < -5/2
Step 2: Subtract 5 from both sides:
x < -5/2 – 5 = -15/2 ≈ -7.5
Step 3: x ∈ Z, so x ≤ -8
Answer: x = {…, -10, -9, -8}

Number line: 
°°°
←───|───|───|───|───|───|───|───|───|───|───→
   -14 -13 -12 -11 -10 -9  -8  -7  -6  -5

iv. 4 – 3x < 13 + x

Step 1: Subtract x from both sides:
4 – 3x – x < 13 + x – x
4 – 4x < 13
Step 2: Subtract 4 from both sides:
-4x < 9
Step 3: Divide by -4 (reverse inequality):
x > -9/4 ≈ -2.25
Step 4: x ∈ Z, so x ≥ -2
Answer: x = {-2, -1, 0, 1, 2, 3, …..}

Number line:
                                °°°
←───|──|──|──|──|──|──|──|──|──|───→
   -4 -3 -2 -1  0  1  2  3  4  5

v. 5 – 4x < 10 – x

Step 1: Subtract 10 from both sides:
5 – 4x – 10 < 10 – x – 10
-4x – 5 < -x
Step 2: Add 4x to both sides:
-4x – 5 + 4x < -x + 4x
-5 < 3x
Step 3: Divide by 3:
-5/3 < x
or x > -5/3 ≈ -1.67
Step 4: x ∈ Z, so x ≥ -1
Answer: x = {-1, 0, 1, 2, 3, 4, ….}

Number line: 
                                °°°
←───|──|──|──|──|──|──|──|──|──|───→
   -4 -3 -2 -1  0  1  2  3  4  5

vi. 10 – 2(1 + 4x) < 20

Step 1: Expand brackets:
10 – 2 – 8x < 20
8 – 8x < 20
Step 2: Subtract 8 from both sides:
-8x < 12
Step 3: Divide by -8 (reverse inequality):
x > -12/8 = -3/2 ≈ -1.5
Step 4: x ∈ Z, so x ≥ -1
Answer: x = {-1, 0, 1, 2, 3, ….}

Number line:
                                °°°
←───|──|──|──|──|──|──|──|──|──|───→
   -4 -3 -2 -1  0  1  2  3  4  5

Q4: Find the solution get of each of the following inequations:

i. 1 – 4x ≥ -1, x ∈ N

Step 1: Subtract 1 from both sides:
1 – 4x – 1 ≥ -1 – 1
-4x ≥ -2
Step 2: Divide by -4 (reverse inequality):
x ≤ 1/2
Step 3: x ∈ N = {1,2,3,…}, but x ≤ 1/2 ⇒ No natural number satisfies
Answer: Φ

ii. -3 ≤ 4x + 1 < 9, x ∈ Z

Step 1: Subtract 1 from all parts:
-3 – 1 ≤ 4x + 1 – 1 < 9 – 1
-4 ≤ 4x < 8
Step 2: Divide all parts by 4:
-1 ≤ x < 2
Step 3: x ∈ Z ⇒ x = -1, 0, 1
Answer: x = -1, 0, 1

iii. 0 < 2x – 5 < 5, x ∈ W

Step 1: Add 5 to all parts:
0 + 5 < 2x – 5 + 5 < 5 + 5
5 < 2x < 10
Step 2: Divide by 2:
5/2 < x < 5
Step 3: x ∈ W = {0,1,2,…}, so x = 3, 4
Answer: x = 3, 4

iv. -3 < x/2 – 1 < 1, x ∈ Z

Step 1: Add 1 to all parts:
-3 + 1 < x/2 – 1 + 1 < 1 + 1
-2 < x/2 < 2
Step 2: Multiply all parts by 2:
-4 < x < 4
Step 3: x ∈ Z ⇒ x = -3, -2, -1, 0, 1, 2, 3
Answer: x = -3, -2, -1, 0, 1, 2, 3

v. -4 < 2x/5 + 1 < -3, x ∈ Z

Step 1: Subtract 1 from all parts:
-4 – 1 < 2x/5 + 1 – 1 < -3 – 1
-5 < 2x/5 < -4
Step 2: Multiply all parts by 5/2:
-25/2 < x < -10
Step 3: x ∈ Z ⇒ x = -12, -11
Answer: x = -12, -11

vi. -1 < 2x/3 + 1 ≤ 5, x ∈ Q

Step 1: Subtract 1 from all parts:
-1 – 1 < 2x/3 + 1 – 1 ≤ 5 – 1
-2 < 2x/3 ≤ 4
Step 2: Multiply all parts by 3/2:
-3 < x ≤ 6
Answer: {x ∈ Q:-3 < x ≤ 6}

vii. -1/4 ≤ 1/2 – x/3 < 2, x ∈ Z

Step 1: Subtract 1/2 from all parts:
-1/4 – 1/2 ≤ 1/2 – x/3 – 1/2 < 2 – 1/2
-3/4 ≤ -x/3 < 3/2
Step 2: Multiply all parts by -3 (reverse inequalities):
9/4 ≥ x > -9/2
or -9/2 < x ≤ 9/4
Step 3: x ∈ Z ⇒ x = -4, -3, -2, -1, 0, 1, 2
Answer: x = -4, -3, -2, -1, 0, 1, 2

viii. 3 + x/4 < 2x/3 + 5, x ∈ Q

Step 1: Subtract 3 from both sides:
x/4 < 2x/3 + 2
Step 2: Subtract 2x/3 from both sides:
x/4 – 2x/3 < 2
(-5x)/12 < 2
Step 3: Multiply both sides by -12/5 (reverse inequality):
x > -24/5
Answer: \({x ∈ Q:x > -4\frac{4}{5}}\)

ix. (3x + 1)/4 ≤ (5x – 2)/3, x ∈ Q

Step 1: Multiply both sides by 12:
3*(3x + 1) ≤ 4*(5x – 2)
9x + 3 ≤ 20x – 8
Step 2: Subtract 9x from both sides:
3 ≤ 11x – 8
Step 3: Add 8 to both sides:
11 ≤ 11x
Step 4: Divide by 11:
1 ≤ x
Answer: {x ∈ Q : x ≥ 1}

x. (1/3)(4x – 1) + 3 ≤ 4 + (2/5)(6x + 2), x ∈ Q

Step 1: Expand both sides:
(4x – 1)/3 + 3 ≤ 4 + (12x + 4)/5
(4x – 1)/3 + 3 ≤ 4 + (12x + 4)/5
Step 2: Simplify constants:
(4x – 1)/3 + 3 = (4x – 1)/3 + 9/3 = (4x + 8)/3
(12x + 4)/5 + 4 = (12x + 4)/5 + 20/5 = (12x + 24)/5
Step 3: Inequation:
(4x + 8)/3 ≤ (12x + 24)/5
Step 4: Multiply both sides by 15:
5*(4x + 8) ≤ 3*(12x + 24)
20x + 40 ≤ 36x + 72
Step 5: Subtract 20x from both sides:
40 ≤ 16x + 72
Step 6: Subtract 72 from both sides:
-32 ≤ 16x
Step 7: Divide by 16:
-2 ≤ x
Answer: {x ∈ Q : x ≥ -2}



Share the Post:

Leave a Comment

Your email address will not be published. Required fields are marked *

Related Posts​

  • Linear Inequations
    Step by Step solutions of Exercise- Competency Focused Questions of RS Aggarwal ICSE Class-8 Maths chapter 16- Linear Inequations by Goyal Brothers Prakashan is provided.
  • Linear Inequations
    Step by Step solutions of Exercise- Assertion-Reason Questions of RS Aggarwal ICSE Class-8 Maths chapter 16- Linear Inequations by Goyal Brothers Prakashan is provided.

Join Our Newsletter

Name
Email
The form has been submitted successfully!
There has been some error while submitting the form. Please verify all form fields again.

Scroll to Top